BC = 15 cm and AC = 13 cm,Calculation:We know, AD = AF, DB = BE, CE = FCThe perimeter of the TRIANGLE = AB + BC + AC = 18 + 15 + 13 = 46That is, AD + AF + BD + BE + CE + CF = 46Or, 2 × (AD + BE + CF) = 46∴ AD + BE + CF = 23

"> BC = 15 cm and AC = 13 cm,Calculation:We know, AD = AF, DB = BE, CE = FCThe perimeter of the TRIANGLE = AB + BC + AC = 18 + 15 + 13 = 46That is, AD + AF + BD + BE + CE + CF = 46Or, 2 × (AD + BE + CF) = 46∴ AD + BE + CF = 23

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A circle inscribed in a triangle ABC touches its sides AB, BC and AC at the points D, E and F, respectively. If AB = 18 cm, BC = 15 cm and AC = 13 cm, then the value of AD + BE + CF is:

SRMJEEE Analytical Geometry in SRMJEEE 9 months ago

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Given:AB = 18 cm, BC = 15 cm and AC = 13 cm,Calculation:We know, AD = AF, DB = BE, CE = FCThe perimeter of the TRIANGLE = AB + BC + AC = 18 + 15 + 13 = 46That is, AD + AF + BD + BE + CE + CF = 46Or, 2 × (AD + BE + CF) = 46∴ AD + BE + CF = 23

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