LENGTHS of tangents from a POINT on a circle are equal.Thus, AP = AR = 6 cmBQ = BP = 5 cmCR = CQ = 7 cmNow, AB = AP + PB = 6 + 5 = 11 cmBC = BQ + QC = 5 + 7 = 12 cmAC = AR + CR = 6 + 7 = 13 cmThe perimeter of ΔABC = AB + BC + AC⇒ The perimeter of ΔABC = 11 + 12 + 13 = 36 cm

"> LENGTHS of tangents from a POINT on a circle are equal.Thus, AP = AR = 6 cmBQ = BP = 5 cmCR = CQ = 7 cmNow, AB = AP + PB = 6 + 5 = 11 cmBC = BQ + QC = 5 + 7 = 12 cmAC = AR + CR = 6 + 7 = 13 cmThe perimeter of ΔABC = AB + BC + AC⇒ The perimeter of ΔABC = 11 + 12 + 13 = 36 cm

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A circle is inscribed in a triangle ABC. It touches sides AB, BC and AC at the points P, Q and R respectively. If BP = 5 cm, CQ = 7 cm and AR = 6 cm, then the perimeter (in cm) of the ΔABC is:

SRMJEEE Analytical Geometry in SRMJEEE 1 year ago

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The LENGTHS of tangents from a POINT on a circle are equal.Thus, AP = AR = 6 cmBQ = BP = 5 cmCR = CQ = 7 cmNow, AB = AP + PB = 6 + 5 = 11 cmBC = BQ + QC = 5 + 7 = 12 cmAC = AR + CR = 6 + 7 = 13 cmThe perimeter of ΔABC = AB + BC + AC⇒ The perimeter of ΔABC = 11 + 12 + 13 = 36 cm

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Posted on 22 Oct 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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