EQUAL so, TRIANGLE ABC and DFE are similar and HENCE corresponding ANGLE will be equal∴ ∠FED = ∠BCA = 180° – (∠ABC + ∠BAC) = 180° – (60° + 80°) = 40°

"> EQUAL so, TRIANGLE ABC and DFE are similar and HENCE corresponding ANGLE will be equal∴ ∠FED = ∠BCA = 180° – (∠ABC + ∠BAC) = 180° – (60° + 80°) = 40°

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Calculate the value of angle FED from the figure shown below.

SRMJEEE Analytical Geometry in SRMJEEE 11 months ago

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AB/DF = 3.8/7.6 = 1/2BC/EF = 6/12 = 1/2AC/ED = 3√3/6√3 = 1/2As, Ratio of corresponding sides of both triangles are EQUAL so, TRIANGLE ABC and DFE are similar and HENCE corresponding ANGLE will be equal∴ ∠FED = ∠BCA = 180° – (∠ABC + ∠BAC) = 180° – (60° + 80°) = 40°

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Posted on 14 Nov 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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