GIVEN:RATIO of AX : BX = 3 : 2Radius of circle = 5 cmCalculation:AX : BX = 3 : 2AB = 2 × 5 = 10 cm⇒ AX = 3/5 × 10 = 6 cm⇒ BX = 10 - 6 = 4 cmPX = XQ (AB is the diameter of given circle and PQ is the perpendicular on AB)As we know,PX × XQ = AX × XB⇒ PX × PX = 6 × 4⇒ PX2 = 24⇒ PX = √24⇒ PX = 2√6Now, PQ = 2PX⇒ PQ = 2 × 2√6∴ PQ = 4√6 "> GIVEN:RATIO of AX : BX = 3 : 2Radius of circle = 5 cmCalculation:AX : BX = 3 : 2AB = 2 × 5 = 10 cm⇒ AX = 3/5 × 10 = 6 cm⇒ BX = 10 - 6 = 4 cmPX = XQ (AB is the diameter of given circle and PQ is the perpendicular on AB)As we know,PX × XQ = AX × XB⇒ PX × PX = 6 × 4⇒ PX2 = 24⇒ PX = √24⇒ PX = 2√6Now, PQ = 2PX⇒ PQ = 2 × 2√6∴ PQ = 4√6 ">
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In a circle, a diameter AB and a chord PQ (which is not a diameter) intersect each other at X perpendicularly. If AX : BX = 3 : 2 and the radius of the circle is 5 cm, then the length of chord PQ is

SRMJEEE Analytical Geometry in SRMJEEE 11 months ago

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GIVEN:RATIO of AX : BX = 3 : 2Radius of circle = 5 cmCalculation:AX : BX = 3 : 2AB = 2 × 5 = 10 cm⇒ AX = 3/5 × 10 = 6 cm⇒ BX = 10 - 6 = 4 cmPX = XQ (AB is the diameter of given circle and PQ is the perpendicular on AB)As we know,PX × XQ = AX × XB⇒ PX × PX = 6 × 4⇒ PX2 = 24⇒ PX = √24⇒ PX = 2√6Now, PQ = 2PX⇒ PQ = 2 × 2√6∴ PQ = 4√6
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Posted on 18 Nov 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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