LET AB is chord and point M is the midpoint of AB, O is the centreGiven, OM = 15 CM and Radius OB = 17 cmIn ΔOMBUsing Pythagoras theorem⇒ (OB)2 = (OM)2 + (MB)2⇒ 172 = 152 + (MB)2⇒ MB = √(289 – 225) = 8As, we know, AB = 2 MBAB = 2 × 8 = 16 cm "> LET AB is chord and point M is the midpoint of AB, O is the centreGiven, OM = 15 CM and Radius OB = 17 cmIn ΔOMBUsing Pythagoras theorem⇒ (OB)2 = (OM)2 + (MB)2⇒ 172 = 152 + (MB)2⇒ MB = √(289 – 225) = 8As, we know, AB = 2 MBAB = 2 × 8 = 16 cm ">
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In a circle of radius 17 cm, a chord is at a distance of 15 cm from the centre of the circle. What is the chord?

SRMJEEE Analytical Geometry in SRMJEEE 9 months ago

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LET AB is chord and point M is the midpoint of AB, O is the centreGiven, OM = 15 CM and Radius OB = 17 cmIn ΔOMBUsing Pythagoras theorem⇒ (OB)2 = (OM)2 + (MB)2⇒ 172 = 152 + (MB)2⇒ MB = √(289 – 225) = 8As, we know, AB = 2 MBAB = 2 × 8 = 16 cm
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Posted on 19 Oct 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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