PERPENDICULAR M and N on chords AB and CD respectively.Now,ΔOBM ≅ ΔODNHence, OM = ON = 6/2 = 3 cmNow,MB2 + OM2 = OB2⇒ MB2 + 32 = 52⇒ MB2 = 25 - 9 = 16⇒ MB = 4 cmAM = 2MB⇒ 2 × 4⇒ 8 cm∴ The length of each chord is 8 cm.