GIVEN, BP : PC = 4 : 3Let BP be 4 unit and PC be 3 unitBC = BP + PC = 4 + 3 = 7 unitIf Q is the MIDPOINT of BP, then BQ = QPBQ = BP/2 = 4/2 = 2 unitar ΔABQ : ar ΔABC = BQ : BC (as HEIGHT will be same for both triangles)ar ΔABQ : ar ΔABC = 2 : 7