PA ∶ PB = 3 ∶ 2 and AB is diameter which is equal to 10 cm,⇒ PA = 3/5 × 10 = 6 cm and PB = 10 - 6 = 4 cmSince AO is the radius of the circle,∴ OP = 6 - 5 = 1 cmIn the same way,ND = 6 cm and NC = 4 cm∴ NO = 6 - 5 = 1 cmNow applying Pythagoras THEOREM in ΔOSN,⇒ OS2 = NS2 + NO2Since OS is the radius of the circle, OS = 5 cm⇒ 25 = NS2 + 1⇒ NS = 2√6∴ SM = (2√6 - 1) cm

"> PA ∶ PB = 3 ∶ 2 and AB is diameter which is equal to 10 cm,⇒ PA = 3/5 × 10 = 6 cm and PB = 10 - 6 = 4 cmSince AO is the radius of the circle,∴ OP = 6 - 5 = 1 cmIn the same way,ND = 6 cm and NC = 4 cm∴ NO = 6 - 5 = 1 cmNow applying Pythagoras THEOREM in ΔOSN,⇒ OS2 = NS2 + NO2Since OS is the radius of the circle, OS = 5 cm⇒ 25 = NS2 + 1⇒ NS = 2√6∴ SM = (2√6 - 1) cm

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In the given figure, CD and AB are diameters of circle and AB and CD are perpendicular to each other. QL and SR are perpendiculars to AB and CD respectively. Radius of circle is 5 cm, PB ∶ PA = 2 ∶ 3 and CN ∶ ND = 2 : 3. What is the length (in cm) of SM?

SRMJEEE Analytical Geometry in SRMJEEE 9 months ago

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Since PA ∶ PB = 3 ∶ 2 and AB is diameter which is equal to 10 cm,⇒ PA = 3/5 × 10 = 6 cm and PB = 10 - 6 = 4 cmSince AO is the radius of the circle,∴ OP = 6 - 5 = 1 cmIn the same way,ND = 6 cm and NC = 4 cm∴ NO = 6 - 5 = 1 cmNow applying Pythagoras THEOREM in ΔOSN,⇒ OS2 = NS2 + NO2Since OS is the radius of the circle, OS = 5 cm⇒ 25 = NS2 + 1⇒ NS = 2√6∴ SM = (2√6 - 1) cm

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Posted on 29 Oct 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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