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Specific conductance of 0.1 M HA is $3.75 \times 10^{- 4} o h m^{- 1} c m^{- 1} .$ If $λ^{\infty} (H A) = 250 o h m^{- 1} c m^{2} m o l^{- 1},$ the dissociation constant $K_{a}$ of HA is :

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Posted on 02 Apr 2024, this text provides information on Standard XI related to Chemistry. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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Specific conductance of 0.1 M HA is 3.75×10−4ohm−1cm−1. If λ∞(HA)=250 ohm−1cm2mol−1, the dissociation constant Ka of HA is :

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Specific conductance of 0.1 M HA is $3.75 \times 10^{- 4} o h m^{- 1} c m^{- 1} .$ If $λ^{\infty} (H A) = 250 o h m^{- 1} c m^{2} m o l^{- 1},$ the dissociation constant $K_{a}$ of HA is :