Fresnel's distance in radio waves

manpreet Best Answer 3 years ago

I am not able to m.tuteehub.com/tag/s">solve the below quem.tuteehub.com/tag/s">stion in wave opticm.tuteehub.com/tag/s">s of Indian ncert m.tuteehub.com/tag/s">syllabum.tuteehub.com/tag/s">s

Two towerm.tuteehub.com/tag/s">s on top of two hillm.tuteehub.com/tag/s">s are 40km apart. The line joining them pam.tuteehub.com/tag/s">sm.tuteehub.com/tag/s">sem.tuteehub.com/tag/s">s 50m above a hill halfm.tuteehub.com/tag/s">s://forum.tuteehub.com/tag/way">way between the towerm.tuteehub.com/tag/s">s. What im.tuteehub.com/tag/s">s the longem.tuteehub.com/tag/s">st wavelength of radio wavem.tuteehub.com/tag/s">s, which can be m.tuteehub.com/tag/s">sent between the towerm.tuteehub.com/tag/s">s without appreciable diffraction effectm.tuteehub.com/tag/s">s ?

The book m.tuteehub.com/tag/s">solvem.tuteehub.com/tag/s">s it thim.tuteehub.com/tag/s">s m.tuteehub.com/tag/s">s://forum.tuteehub.com/tag/way">way,

The hillm.tuteehub.com/tag/s">s will not obm.tuteehub.com/tag/s">struct the tranm.tuteehub.com/tag/s">smitted radio wavem.tuteehub.com/tag/s">s,if over the halfm.tuteehub.com/tag/s">s://forum.tuteehub.com/tag/way">way dim.tuteehub.com/tag/s">stance (Z¬F) between the hillm.tuteehub.com/tag/s">s,the m.tuteehub.com/tag/s">spreading of the m.tuteehub.com/tag/s">signal im.tuteehub.com/tag/s">s limited to the dim.tuteehub.com/tag/s">stance(a) of the line of m.tuteehub.com/tag/s">sight from the hillm.tuteehub.com/tag/s">s,

Here,Frem.tuteehub.com/tag/s">snel’m.tuteehub.com/tag/s">s dim.tuteehub.com/tag/s">stance Z¬F = 20km = 20 x 103m,a = 50m, Now, Z¬F = a²/λ,λ = 502/20 x 103 = 0.125m.

My concern im.tuteehub.com/tag/s">s in the formulae of Frem.tuteehub.com/tag/s">snel’m.tuteehub.com/tag/s">s dim.tuteehub.com/tag/s">stance Z¬F = a²/λ, Z¬F im.tuteehub.com/tag/s">s the dim.tuteehub.com/tag/s">stance between the m.tuteehub.com/tag/s">slit and the m.tuteehub.com/tag/s">screen,a im.tuteehub.com/tag/s">s the m.tuteehub.com/tag/s">size of the aperture, here I am not finding any aperture am.tuteehub.com/tag/s">s above the middle hill the m.tuteehub.com/tag/air">air m.tuteehub.com/tag/s">spreadm.tuteehub.com/tag/s">s till infinity,

Z¬F in thim.tuteehub.com/tag/s">s cam.tuteehub.com/tag/s">se im.tuteehub.com/tag/s">s the dim.tuteehub.com/tag/s">stance between the aperture and the m.tuteehub.com/tag/s">screen, Even though m not finding any m.tuteehub.com/tag/s">slit or m.tuteehub.com/tag/s">screen, Zf m.tuteehub.com/tag/s">should be the dim.tuteehub.com/tag/s">stance between the middle hill and the third hill but in the book it im.tuteehub.com/tag/s">s between the firm.tuteehub.com/tag/s">st hill and the middle hill,

I am not getting what the m.tuteehub.com/tag/s">situation im.tuteehub.com/tag/s">s all about in thim.tuteehub.com/tag/s">s quem.tuteehub.com/tag/s">stion and how to go about m.tuteehub.com/tag/s">solving it, Thankm.tuteehub.com/tag/s">s.