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Course Queries Syllabus Queries 2 years ago
Posted on 16 Aug 2022, this text provides information on Syllabus Queries related to Course Queries. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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Let R=C[x,y]⟨x2−y2−com/tag/1">1⟩R=C[x,y]⟨x2−y2−com/tag/1">1⟩. Prove that (1) RR is an integral domain.(2) Any nonzero prime ideal of RR is maximal.
Let R=C[x,y]⟨x2−y2−com/tag/1">1⟩R=C[x,y]⟨x2−y2−com/tag/1">1⟩.
Prove that
(1) RR is an integral domain.(2) Any nonzero prime ideal of RR is maximal.
My idea:
(1) The first part is easy. Since x2−y2−com/tag/1">1∈C[y][x]x2−y2−com/tag/1">1∈C[y][x] is Eisenstein with respect to the prime y+iy+i, it is irreducible. Hence the ideal generated by it is a prime ideal.
(2) I am struggling with this part. I have one approach (not sure if correct).
Approach : Let I=⟨x2−y2−com/tag/1">1⟩I=⟨x2−y2−com/tag/1">1⟩. Then R=C[x,y]/IR=C[x,y]/I. Any ideal of RR is of the form J/I REPLY 0 views 0 likes 0 shares Facebook Twitter Linked In WhatsApp
Solution f="https://forum.tuteehub.com/tag/1">1. The second part is also very simple. Indeed, recall that if k=k¯¯¯k=k¯ is an algebraically closed field every prime ideal of k[X,Y]k[X,Y] is of the form ⟨X−x,Y−y⟩⟨X−x,Y−y⟩ or of the form (f(X,Y))(f(X,Y)) with f(X,Y)∈k[X,Y]f(X,Y)∈k[X,Y] irreducible. If you take k[X,Y]/Ik[X,Y]/I for some ideal II, we have that the set of the prime ideals of k[X,Y]/Ik[X,Y]/I is simply the set of the primes in k[X,Y]k[X,Y] of the primes which contain II. Now, since the polynomial X2−Y2−f="https://forum.tuteehub.com/tag/1">1 REPLY 0 views 0 likes 0 shares Facebook Twitter Linked In WhatsApp
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