Speak now
Please Wait Image Converting Into Text...
Embark on a journey of knowledge! Take the quiz and earn valuable credits.
Challenge yourself and boost your learning! Start the quiz now to earn credits.
Unlock your potential! Begin the quiz, answer questions, and accumulate credits along the way.
Course Queries Syllabus Queries 2 years ago
Posted on 16 Aug 2022, this text provides information on Syllabus Queries related to Course Queries. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
Turn Your Knowledge into Earnings.
In our syllabus, we proved the local inverse function theorem: Let f:E→Rnf:E→Rn with E⊆RnE⊆Rn open be C1C1. If a⃗ ∈Ea→∈E with detf′(a⃗ )≠0detf′(a→)≠0, then there exist open sets U∋a⃗ U∋a→ and V∋f(a⃗ )V∋f(a→) such that f:U→Vf:U→V is a C1C1-diffeomorphism.
I have two questions which involve this theorem.
First, I am asked to prove the following 'global' version of the inverse function theorem, which states: Let f:E→font-style: inherit; font-variant: inherit; font-weight: inherit; font-stretch: inherit; line-height: normal; font-family:
I proof the global version of the inverse function theorem using the following local version:
Inverse function theorem [local]. Let E⊂RnE⊂Rn open, and let f:E→Rnf:E→Rn be a C1C1 map. Let a∈Ea∈E be such that det(f′(a))≠0det(f′(a))≠0. Then there exists open balls U∋aU∋a and V∋f(a)V∋f(a) such that f:U→Vf:U→V is a C1C1 diffeomorphism.
I will proof:
Inverse function theorem [global] Let E⊂RnE⊂Rn open, and let f:E→Rnf:E→Rn be an injective REPLY 0 views 0 likes 0 shares Facebook Twitter Linked In WhatsApp
No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.
Course Queries 4 Answers
Course Queries 5 Answers
Course Queries 1 Answers
Course Queries 3 Answers
Ready to take your education and career to the next level? Register today and join our growing community of learners and professionals.