The equation yp−y=x in finite fields.

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manpreet Tuteehub forum best answer Best Answer 2 years ago

 

Define the trace by

Tr:Fpn Fpn:x  x+xp++xpn1Tr:Fpn ⟶Fpn:x ⟼ x+xp+⋯+xpn−1

Now define yet another mapping:

L:Fpn Fpn:x  xpxL:Fpn ⟶Fpn:x ⟼ xp−x

 

I know that this is a linear mapping. My syllabus stated the following I could't prove:

  • The kernel of the map is FpFp.
  • If the equation y114" class="mi" style="margin: 0px; padding: 0px; border: 0px; font-style: inherit; font-variant: inherit; font-weight: inherit; font-stretch: inherit; lin
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manpreet 2 years ago

The first claim follows from the fact that the Galois group of Fpn/FpFpn/Fp is generated by the Frobenius map xxpx↦xp. Thus, from Galois theory, the subfield of FpnFpn fixed by G(Fpn/Fp)G(Fpn/Fp) is exactly FpFp. For your second statement, recall that Tr(yp)=Tr(y)Tr⁡(yp)=Tr⁡(y), now apply TrTr on both sides of the equation.


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