Why is processing a sorted array faster than processing an unsorted array?

Digital Marketing Facebook Marketing API 3 years ago

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_x000D_ _x000D_ Here is a piece of C++ code that shows some very peculiar behavior. For some strange reason, sorting the data miraculously makes the code almost six times faster: #include #include #include int main() { // Generate data const unsigned arraySize = 32768; int data[arraySize]; for (unsigned c = 0; c < arraySize; ++c) data[c] = std::rand() % 256; // !!! With this, the next loop runs faster. std::sort(data, data + arraySize); // Test clock_t start = clock(); long long sum = 0; for (unsigned i = 0; i < 100000; ++i) { // Primary loop for (unsigned c = 0; c < arraySize; ++c) { if (data[c] >= 128) sum += data[c]; } } double elapsedTime = static_cast(clock() - start) / CLOCKS_PER_SEC; std::cout << elapsedTime << std::endl; std::cout << "sum = " << sum << std::endl; } Without std::sort(data, data + arraySize);, the code runs in 11.54 seconds. With the sorted data, the code runs in 1.93 seconds. Initially, I thought this might be just a language or compiler anomaly, so I tried Java: import java.util.Arrays; import java.util.Random; public class Main { public static void main(String[] args) { // Generate data int arraySize = 32768; int data[] = new int[arraySize]; Random rnd = new Random(0); for (int c = 0; c < arraySize; ++c) data[c] = rnd.nextInt() % 256; // !!! With this, the next loop runs faster Arrays.sort(data); // Test long start = System.nanoTime(); long sum = 0; for (int i = 0; i < 100000; ++i) { // Primary loop for (int c = 0; c < arraySize; ++c) { if (data[c] >= 128) sum += data[c]; } } System.out.println((System.nanoTime() - start) / 1000000000.0); System.out.println("sum = " + sum); } } With a similar but less extreme result. My first thought was that sorting brings the data into the cache, but then I thought how silly that was because the array was just generated. What is going on? Why is processing a sorted array faster than processing an unsorted array? The code is summing up some independent terms, so the order should not matter.

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