CONTROL instrument, the controlling torque is given by,\(\begin{array}{l} {T_c} = {K_c}\THETA \\ {T_d} \propto I \end{array}\)At equilibrium position, TC = TD\(\RIGHTARROW I \propto \theta\)Hence in spring control, the scale is uniformIn gravity control, a small weight is placed on an arm attached to the moving system. The position of this weight is adjustable. This weight produces a controlling torque due to gravity.This controlling torque is given by,\(\begin{array}{l} {T_c} = {K_g}\sin \theta \\ {T_d} \propto I \end{array}\)At equilibrium position, TC = TD\(\Rightarrow I \propto \sin \theta\)Hence in gravity control, the scale is non-uniform.Therefore, both statement (I) and Statement (II) are INDIVIDUALLY true and Statement (II) is the correct explanation of Statement (I)