FEEDBACK.Upper cut-off Frequency with negative feedback is given by:\({f_H} = {f_h}\left( {1 + Aβ } \right)\)A = open loop gainβ = Negative feedback gainCalculation:Givne: FH = 60 KHZ, A = 500, β = 1/100Upper cut-off Frequency with negative feedback will be:\({f_H} = {60}\left( {1 + 500\times \frac{1}{100} } \right)~kHz\)fH = 60K × 6fH = 360 kHz

"> FEEDBACK.Upper cut-off Frequency with negative feedback is given by:\({f_H} = {f_h}\left( {1 + Aβ } \right)\)A = open loop gainβ = Negative feedback gainCalculation:Givne: FH = 60 KHZ, A = 500, β = 1/100Upper cut-off Frequency with negative feedback will be:\({f_H} = {60}\left( {1 + 500\times \frac{1}{100} } \right)~kHz\)fH = 60K × 6fH = 360 kHz

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An amplifier with mid-band gain |A| = 500 has negative feedback |b| = 1/100. If the upper cut off frequency without feedback were at 60 kHz, then with feedback it would become

Electronics & Communication Engineering Op-Amp And Its Applications in Electronics & Communication Engineering . 7 months ago

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Concept:Upper cut-off Frequency: The upper cut-off frequency increases as bandwidth increases with Negative FEEDBACK.Upper cut-off Frequency with negative feedback is given by:\({f_H} = {f_h}\left( {1 + Aβ } \right)\)A = open loop gainβ = Negative feedback gainCalculation:Givne: FH = 60 KHZ, A = 500, β = 1/100Upper cut-off Frequency with negative feedback will be:\({f_H} = {60}\left( {1 + 500\times \frac{1}{100} } \right)~kHz\)fH = 60K × 6fH = 360 kHz

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Posted on 29 Oct 2024, this text provides information on Electronics & Communication Engineering related to Op-Amp And Its Applications in Electronics & Communication Engineering. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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