CONCEPT:For reversible heat ENGINE efficiency\(\begin{array}{l} \ETA = 1 - \frac{{{T_R}}}{{{T_S}}}\end{array}\)\(\begin{array}{l} \eta = \frac{W}{{{Q_S}}} = 1 - \frac{{{Q_R}}}{{{Q_S}}}\\ \end{array}\)Calculation:\(\begin{array}{l} \eta = 1 - \frac{{{T_R}}}{{{T_S}}} = 1 - \frac{{300}}{{500}} = 0.4\\ \eta = \frac{W}{{{Q_S}}} = 1 - \frac{{{Q_R}}}{{{Q_S}}}\\ {Q_R} = 150\;KW \end{array}\)∴ Q = 150 kW or 150 kJ/s "> CONCEPT:For reversible heat ENGINE efficiency\(\begin{array}{l} \ETA = 1 - \frac{{{T_R}}}{{{T_S}}}\end{array}\)\(\begin{array}{l} \eta = \frac{W}{{{Q_S}}} = 1 - \frac{{{Q_R}}}{{{Q_S}}}\\ \end{array}\)Calculation:\(\begin{array}{l} \eta = 1 - \frac{{{T_R}}}{{{T_S}}} = 1 - \frac{{300}}{{500}} = 0.4\\ \eta = \frac{W}{{{Q_S}}} = 1 - \frac{{{Q_R}}}{{{Q_S}}}\\ {Q_R} = 150\;KW \end{array}\)∴ Q = 150 kW or 150 kJ/s ">
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A heat engine is supplied with 250 kJ/s of heat at constant fluid temperature of 227°C. The heat is rejected at 27°C. The cycle is reversible, if the amount of heat rejected is

Fluid Mechanics First Law Thermodynamics in Fluid Mechanics . 7 months ago

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CONCEPT:For reversible heat ENGINE efficiency\(\begin{array}{l} \ETA = 1 - \frac{{{T_R}}}{{{T_S}}}\end{array}\)\(\begin{array}{l} \eta = \frac{W}{{{Q_S}}} = 1 - \frac{{{Q_R}}}{{{Q_S}}}\\ \end{array}\)Calculation:\(\begin{array}{l} \eta = 1 - \frac{{{T_R}}}{{{T_S}}} = 1 - \frac{{300}}{{500}} = 0.4\\ \eta = \frac{W}{{{Q_S}}} = 1 - \frac{{{Q_R}}}{{{Q_S}}}\\ {Q_R} = 150\;KW \end{array}\)∴ Q = 150 kW or 150 kJ/s
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Posted on 03 Dec 2024, this text provides information on Fluid Mechanics related to First Law Thermodynamics in Fluid Mechanics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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