In a reversible isothermal expansion process fluid expands from 10 bar and 2 m3 to 2 bar and 10 m3. During the process the heat supplied is at the rate of 100 kW. What is the rate of work done during the process

Explanation:Heat transfer in the constant temperature process by first law of thermodynamics is given as:Q = U + Wwhere, Q = heat supplied. U = 0 = Internal energy, W = work doneSo, the heat transfer equation is, Q = W = 100 kW ProcessWork DoneConstant Pressure (Isobaric / Isopiestic)W1-2 = P(V2 – V1)Constant Volume (Isochoric)W1-2 = 0Isothermal\({W_{1 - 2}} = {p_1}{V_1}\ln \left( {\FRAC{{{p_1}}}{{{p_2}}}} \RIGHT) = {p_2}{V_2}\ln \left( {\frac{{{p_1}}}{{{p_2}}}} \right)\)PolytropicFor Adiabatic (n = γ = 1.4)\({W_{1 - 2}} = \frac{{{p_1}{V_1} - {p_2}{V_2}}}{{n - 1}} = \frac{{{p_1}{V_1}}}{{n - 1}}\left[ {1 - {{\left( {\frac{{{p_2}}}{{{p_1}}}} \right)}^{\frac{{n - 1}}{n}}}} \right]\)