NEED to factorisex3 - 24X2 + 191x - 504⇒ x3 - 17x2 + 72x - 7x2 + 119x - 504⇒ x(x2 - 17X + 72) - 7(x2 - 17x - 72)⇒ (x - 7) (x2 - 17x + 72)⇒ (x - 7) (x - 8) (x - 9) Thus the Zeros of the POLYNOMIAL are 7, 8, 9

"> NEED to factorisex3 - 24X2 + 191x - 504⇒ x3 - 17x2 + 72x - 7x2 + 119x - 504⇒ x(x2 - 17X + 72) - 7(x2 - 17x - 72)⇒ (x - 7) (x2 - 17x + 72)⇒ (x - 7) (x - 8) (x - 9) Thus the Zeros of the POLYNOMIAL are 7, 8, 9

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Find the zeros of the polynominal -x3 - 24x2 + 191x - 504

General Aptitude Algebra in General Aptitude 10 months ago

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To find the zeros we NEED to factorisex3 - 24X2 + 191x - 504⇒ x3 - 17x2 + 72x - 7x2 + 119x - 504⇒ x(x2 - 17X + 72) - 7(x2 - 17x - 72)⇒ (x - 7) (x2 - 17x + 72)⇒ (x - 7) (x - 8) (x - 9) Thus the Zeros of the POLYNOMIAL are 7, 8, 9

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