GIVEN:y = 3 + 2√2Calculation:Y2 = (3 + 2√2)2 ⇒ y2 = 9 + (4 × 2) + 12√2 = 17 + 12√2 = 34 (approx.)y-2 = (1/y2) = 1/34Now,√2(y2 - y-2) = √2 × (34 - (1/34))⇒ √2 × (1155/34) = 48.04 ≈ 48 "> GIVEN:y = 3 + 2√2Calculation:Y2 = (3 + 2√2)2 ⇒ y2 = 9 + (4 × 2) + 12√2 = 17 + 12√2 = 34 (approx.)y-2 = (1/y2) = 1/34Now,√2(y2 - y-2) = √2 × (34 - (1/34))⇒ √2 × (1155/34) = 48.04 ≈ 48 ">
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If y = 3 + 2√2, find the value of √2(y2 - y-2). (approximately)

General Aptitude Algebra in General Aptitude 10 months ago

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GIVEN:y = 3 + 2√2Calculation:Y2 = (3 + 2√2)2 ⇒ y2 = 9 + (4 × 2) + 12√2 = 17 + 12√2 = 34 (approx.)y-2 = (1/y2) = 1/34Now,√2(y2 - y-2) = √2 × (34 - (1/34))⇒ √2 × (1155/34) = 48.04 ≈ 48
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