X2 – y2 = 35⇒ (X + y) (x – y) = 5 × 7Hence, x = 6 and y = 1AND,(x + y) (x – y) = 1 × 35Hence, x = 18 and y = 17Hence, 2 PAIR is POSSIBLE. "> X2 – y2 = 35⇒ (X + y) (x – y) = 5 × 7Hence, x = 6 and y = 1AND,(x + y) (x – y) = 1 × 35Hence, x = 18 and y = 17Hence, 2 PAIR is POSSIBLE. ">

How many pairs of natural numbers are there such that the difference of their squares is 35?

General Aptitude Algebra in General Aptitude . 8 months ago

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X2 – y2 = 35⇒ (X + y) (x – y) = 5 × 7Hence, x = 6 and y = 1AND,(x + y) (x – y) = 1 × 35Hence, x = 18 and y = 17Hence, 2 PAIR is POSSIBLE.

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