GIVEN:X : y = 2 : 1Calculation:x : y = 2 : 1(x2 - y2)/(x2 + y2) ----(i)Take common y2 in numerator or DENOMINATOR in equation (i)⇒ y2[(x2/y2) - 1]/y2[(x2/y2) + 1]⇒ [(x2/y2) - 1]/[(x2/y2) + 1]Put the value of x/y = 2⇒ [(2)2 - 1]/[(2)2 + 1]⇒ (4 - 1)/(4 + 1)⇒ 3/5∴ The value of (x2 - y2) : (x2 + y2) is 3 : 5. x : y = 2 : 1(x2 - y2)/(x2 + y2) ----(i)Put x = 2k and y = k in equation (i) ⇒ [(2k)2 - K2]/[(2k)2 + k2]⇒ (4k2 - k2)/(4k2 + k2)⇒ 3k2/5k2⇒ 3/5∴ The value of (x2 - y2) : (x2 + y2​) is 3 : 5. "> GIVEN:X : y = 2 : 1Calculation:x : y = 2 : 1(x2 - y2)/(x2 + y2) ----(i)Take common y2 in numerator or DENOMINATOR in equation (i)⇒ y2[(x2/y2) - 1]/y2[(x2/y2) + 1]⇒ [(x2/y2) - 1]/[(x2/y2) + 1]Put the value of x/y = 2⇒ [(2)2 - 1]/[(2)2 + 1]⇒ (4 - 1)/(4 + 1)⇒ 3/5∴ The value of (x2 - y2) : (x2 + y2) is 3 : 5. x : y = 2 : 1(x2 - y2)/(x2 + y2) ----(i)Put x = 2k and y = k in equation (i) ⇒ [(2k)2 - K2]/[(2k)2 + k2]⇒ (4k2 - k2)/(4k2 + k2)⇒ 3k2/5k2⇒ 3/5∴ The value of (x2 - y2) : (x2 + y2​) is 3 : 5. ">
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If x : y = 2 : 1, then (x2 – y2 ) : (x2 + y2 ) is:

General Aptitude Algebra in General Aptitude . 8 months ago

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GIVEN:X : y = 2 : 1Calculation:x : y = 2 : 1(x2 - y2)/(x2 + y2) ----(i)Take common y2 in numerator or DENOMINATOR in equation (i)⇒ y2[(x2/y2) - 1]/y2[(x2/y2) + 1]⇒ [(x2/y2) - 1]/[(x2/y2) + 1]Put the value of x/y = 2⇒ [(2)2 - 1]/[(2)2 + 1]⇒ (4 - 1)/(4 + 1)⇒ 3/5∴ The value of (x2 - y2) : (x2 + y2) is 3 : 5. x : y = 2 : 1(x2 - y2)/(x2 + y2) ----(i)Put x = 2k and y = k in equation (i) ⇒ [(2k)2 - K2]/[(2k)2 + k2]⇒ (4k2 - k2)/(4k2 + k2)⇒ 3k2/5k2⇒ 3/5∴ The value of (x2 - y2) : (x2 + y2​) is 3 : 5.
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