GIVEN:Side of each cube = 4 cmFormula:Total surface area of cube = 6a2Total surface area of cuboid = 2 (LB + bh + HL)Calculation:Total surface area of all three cube = 3 × 6 × 42⇒ Total surface area of all three cube = 18 × 16⇒ Total surface area of all three cube = 288 cm2If all three cube joined end to end, then length of cuboid = 3 × 4 = 12 cmBreadth of cuboid = 4 cmHeight of cubod = 4 cmTotal surface area of cuboid = 2 (12 × 4 + 4 × 4 + 4 × 12)⇒ Total surface area of cuboid = 2 × (48 + 16 + 48)⇒ Total surface area of cuboid = 2 × 112 = 224 cm2∴ Required ratio = 224 : 288 = 7 : 9 "> GIVEN:Side of each cube = 4 cmFormula:Total surface area of cube = 6a2Total surface area of cuboid = 2 (LB + bh + HL)Calculation:Total surface area of all three cube = 3 × 6 × 42⇒ Total surface area of all three cube = 18 × 16⇒ Total surface area of all three cube = 288 cm2If all three cube joined end to end, then length of cuboid = 3 × 4 = 12 cmBreadth of cuboid = 4 cmHeight of cubod = 4 cmTotal surface area of cuboid = 2 (12 × 4 + 4 × 4 + 4 × 12)⇒ Total surface area of cuboid = 2 × (48 + 16 + 48)⇒ Total surface area of cuboid = 2 × 112 = 224 cm2∴ Required ratio = 224 : 288 = 7 : 9 ">

Three cubes of side 4 cm each are joined end to end to form a cuboid. The surface area of the resulting cuboid and total surface area of the three cubes are in the respective ratio of_____.

General Knowledge General Awareness in General Knowledge 10 months ago

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GIVEN:Side of each cube = 4 cmFormula:Total surface area of cube = 6a2Total surface area of cuboid = 2 (LB + bh + HL)Calculation:Total surface area of all three cube = 3 × 6 × 42⇒ Total surface area of all three cube = 18 × 16⇒ Total surface area of all three cube = 288 cm2If all three cube joined end to end, then length of cuboid = 3 × 4 = 12 cmBreadth of cuboid = 4 cmHeight of cubod = 4 cmTotal surface area of cuboid = 2 (12 × 4 + 4 × 4 + 4 × 12)⇒ Total surface area of cuboid = 2 × (48 + 16 + 48)⇒ Total surface area of cuboid = 2 × 112 = 224 cm2∴ Required ratio = 224 : 288 = 7 : 9

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