Bash to Call PHP, Wait for PHP Process to finish?

manpreet Best Answer 2 years ago

Here is my bash script

#!/bin/bash
timestamp() {
  date +"%T"
}
pushd 'httpdocs/DIR1/DIR2'; 
file="Lock3.key"
if [ -f "$file" ]
then
    echo "$file found, Session is already in progress" $(date)
else
    echo "$file was not found, Its safe to start the script"  $(date)
    echo "Running Ebay Stock Only Script" $(date)
#Its possible to double check if the script is running by checking memory.
#ps aux | grep "php Cron-Run.php" (Not safe)
php Cron-Run.php > Output.log
echo "Finished Running Script, Lock file is deleted by PHP, Now exiting" $(date)
fi
exit

This is run from a cron job, and works. But all I want is the last echo to only run when the PHP process has finished (it will run for a hour) and, when the email comes through, it would be nice to see the output of the last echo with the associated time.

At the moment, the echo runs two seconds after the PHP script is called.

manpreet 2 years ago

I was able to pause / wait for the process to finish by using the wait function.

an example of the working segment:

#!/bin/bash
timestamp() {
  date +"%T"
}
pushd 'httpdocs/DIR1/DIR2'; 
file="Lock3.key"
if [ -f "$file" ]
then
    echo "$file found, Session is already in progress" $(date)
else
    echo "$file was not found, Its safe to start the script"  $(date)
    echo "Running Ebay Stock Only Script" $(date)
#Its possible to double check if the script is running by checking memory.
#ps aux | grep "php Cron-Run.php" (Not safe)
php Cron-Run.php > Output.log
wait
echo "Finished Running Script, Lock file is deleted by PHP, Now exiting" $(date)
fi
exit