Find all keys JSON - RapidJSON

manpreet Best Answer 3 years ago

I need to find all the keys in the kTypeNames[] with rapidJSON library. Trying to iterate all the nodes but I'm missing something; here's the code:

#include 
#include 
#include <string>
#include <bits/stdc++.h>
#include 
#include "rapidjson/document.h"
#include "rapidjson/writer.h"
#include "rapidjson/stringbuffer.h"

using namespace rapidjson;

using namespace std;

const char* kTypeNames[] = { "id", "text", "templ_text", "key" };

int main(int argc, char* argv[]) {

string line;
char json[65000];
std::ifstream file(argv[1]);
unsigned long i = 0;
if (file.is_open()) {
    while (!file.eof()) {
        file.get(json[i]);
        i++;
    }
    file.close();
} else {
    cout << "Unable to open file";
}

Document document;
document.Parse(json);
printf("\n\n\n\n*********Access values in document**********\n");

assert(document.IsObject());

for (auto Typename : kTypeNames) {
    if (document.HasMember(Typename)) {

        cout << "\n";
        cout << Typename << ":" << document[Typename].GetString()<< endl;
        cout << "\n";
    }
    else {
        cout << "\n None\n";
    }
 }

It does not works with a nested JSON.

{
"node": {
    "text": "find this",
    "templ_text": "don't find",
    "ver": "don't find"
},
"ic": "",
"text": "also this",
"templ_text": "don't care",
"par": {
    "SET": {
        "vis": "<blabla>",
        "text": "keyFound",
        "templ_text": "don't need this"
    }

                                                

                                                                                                        
                                                    
                                                
                                                

                                                    

                                                        
                                                            0
                                                            views 

                                                            0
                                                                likes 
                                                            
                                                            

                                                            0
                                                            shares
                                                            


    

         Facebook
        
         Twitter
        
        
         Linked In 
        
          WhatsApp