Speak now
Please Wait Image Converting Into Text...
Embark on a journey of knowledge! Take the quiz and earn valuable credits.
Challenge yourself and boost your learning! Start the quiz now to earn credits.
Unlock your potential! Begin the quiz, answer questions, and accumulate credits along the way.
General Tech Bugs & Fixes 2 years ago
Posted on 16 Aug 2022, this text provides information on Bugs & Fixes related to General Tech. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
Turn Your Knowledge into Earnings.
I need to find all the keys in the kTypeNames[] with rapidJSON library. Trying to iterate all the nodes but I'm missing something; here's the code:
#include #include #include <string> #include <bits/stdc++.h> #include #include "rapidjson/document.h" #include "rapidjson/writer.h" #include "rapidjson/stringbuffer.h" using namespace rapidjson; using namespace std; const char* kTypeNames[] = { "id", "text", "templ_text", "key" }; int main(int argc, char* argv[]) { string line; char json[65000]; std::ifstream file(argv[1]); unsigned long i = 0; if (file.is_open()) { while (!file.eof()) { file.get(json[i]); i++; } file.close(); } else { cout << "Unable to open file"; } Document document; document.Parse(json); printf("\n\n\n\n*********Access values in document**********\n"); assert(document.IsObject()); for (auto Typename : kTypeNames) { if (document.HasMember(Typename)) { cout << "\n"; cout << Typename << ":" << document[Typename].GetString()<< endl; cout << "\n"; } else { cout << "\n None\n"; } }
It does not works with a nested JSON.
{ "node": { "text": "find this", "templ_text": "don't find", "ver": "don't find" }, "ic": "", "text": "also this", "templ_text": "don't care", "par": { "SET": { "vis": "<blabla>", "text": "keyFound", "templ_text": "don't need this" } REPLY 0 views 0 likes 0 shares Facebook Twitter Linked In WhatsApp
void parse(rapidjson::Value & value) { for(auto Typename : kTypeNames) { if(value.HasMember(Typename)) { if(value[Typename].IsString()) { std::cout << Typename << ": " << value[Typename].GetString() << std::endl; } } } for(auto member = value.MemberBegin(); member != value.MemberEnd(); ++member) { if(member->value.IsObject()) { parse(member->value); } } }
No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.
General Tech 9 Answers
General Tech 7 Answers
General Tech 3 Answers
General Tech 2 Answers
Ready to take your education and career to the next level? Register today and join our growing community of learners and professionals.