Sort array alphanumerically

manpreet Best Answer 3 years ago

I have array like below , I want to sort it alphanumerically by ascending or descending in faster way.

[
  "NFO:BANKNIFTY1931428900CE",
  "NFO:BANKNIFTY1931429000CE",
  "NFO:BANKNIFTY1931429500CE",
  "NFO:BANKNIFTY1931429400CE",
  "NFO:BANKNIFTY1931429300CE",
  "NFO:BANKNIFTY1931429200CE"
]

I want to sort it like below , descending or ascending

[
  "NFO:BANKNIFTY1931429500CE",
  "NFO:BANKNIFTY1931429400CE",
  "NFO:BANKNIFTY1931429300CE",
  "NFO:BANKNIFTY1931429200CE",
  "NFO:BANKNIFTY1931429000CE",
  "NFO:BANKNIFTY1931428900CE",
]

I tried something like below , but it does not sort properly and its slow too.

function sort() { var arr = disorderedArray; arr.sort(function(a, b) { a = a.split(" "); b = b.split(" "); var an = parseInt(a[0], 10); var bn = parseInt(b[0], 10); return an < bn ? 1 : (an > bn ? -1 : (a[1] < b[1] ? -1 : (a[1] > b[1] ? 1 : 0))); }); console.log(arr.reverse()); }

Note: Sometimes it can involve mix of lowercase letters.

manpreet 3 years ago

Sort array by alphanumerically using localeCompare method.

The localeCompare() method returns a number indicating whether a reference string comes before or after or is the same as the given string in sort order.

const sortAlphaNum = (a, b) => a.localeCompare(b, 'en', { numeric: true })
console.log([
  "NFO:BANKNIFTY1931428900CE",
  "NFO:BANKNIFTY1931429000CE",
  "NFO:BANKNIFTY1931429500CE",
  "NFO:BANKNIFTY1931429400CE",
  "NFO:BANKNIFTY1931429300CE",
  "NFO:BANKNIFTY1931429200CE"
].sort(sortAlphaNum))