Google Core IoT Device Offline Event or Connection Status

Internet of Things IoT Frameworks 2 years ago

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_x000D_ _x000D_ Does anybody know of an easy way to trigger an event when a device on Google Core IoT goes offline? Before I switched to Google's IoT implementation, this was very easily handled by triggering an event when MQTT disconnects, but it seems Google has no easy way of doing this. Does anybody know if there is something planned for this? Who's back do I need to scratch to get them to see that something like this is a basic requirement for IoT device management! Other platforms like AWS and Microsoft already have this implemented (or some way to handle it easily): https://docs.aws.amazon.com/iot/latest/developerguide/life-cycle-events.html Device connectivity(online/offline)status with the Auzure iot hub I wish I had known this before writing all my code and implementing my setup using Google's IoT platform, I guess that's my fault for assuming something so simple and that should be standard for IoT devices would be available. How are you going to compete with other IoT providers if you can't even provide basic offline/online events?! My reply in this SO question shows how I had to write 100+ lines of code just to create a firebase function to check if a device is online (but that still doesn't handle offline events, and is just a hack for something that should be native to ANY IoT service provider!): https://stackoverflow.com/a/54609628/378506 I'm hoping someone else has figured out a way to do this, as i've spent numerous days searching SO, Google, Google Core IoT Documentation, and still have not found anything. Even if MQTT Last Will was supported we could make that work, but even that IS NOT SUPPORTED by Google (https://cloud.google.com/iot/docs/requirements) ... come on guys!

Posted on 16 Aug 2022, this text provides information on IoT Frameworks related to Internet of Things. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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