Index based Data structure in Java [duplicate]

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_x000D_ _x000D_ _x000D_ This question already has an answer here:_x000D_ _x000D_ _x000D_ When to use LinkedList over ArrayList in Java?_x000D_ _x000D_ 32 answers_x000D_ _x000D_ _x000D_ _x000D_ _x000D_ I have some values (:a , :a , :b , :c , :f , :f) which I want to store in a unique index based Data structure, which I can later iterate over to get my values. Can any one please let me know which is the simplest way ? E.g :a :a :b :c :f :f LATER, Iterate on the DATA STRUCTURE based upon, the INDEX, to get my values Thanks in advance

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manpreet Tuteehub forum best answer Best Answer 2 years ago
_x000D_ If I understand your question, you could use a List like so public static void main(String[] args) { List al = Arrays.asList(":a", ":a", ":b", ":c", ":f", ":f"); for (int i = 0; i < al.size(); i++) { System.out.printf("%d. %s%n", 1 + i, al.get(i)); } } Output is (note: the index starts at 0, so I added one above to get your requested output) 1. :a 2. :a 3. :b 4. :c 5. :f 6. :f

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