180}^{o}}\Rightarrow x={{18}^{o}}\] Hence the angles are \[{{18}^{o}},\text{ }{{36}^{o}},\text{ }{{126}^{o}}\] Greatest side \[\propto \]\[\sin ({{126}^{o}})\] Smallest side \[\propto \] \[\sin ({{18}^{o}})\] and ratio\[=\FRAC{\sin {{126}^{o}}}{\sin ({{18}^{o}})}=\frac{\sqrt{5}+1}{\sqrt{5}-1}\].

"> 180}^{o}}\Rightarrow x={{18}^{o}}\] Hence the angles are \[{{18}^{o}},\text{ }{{36}^{o}},\text{ }{{126}^{o}}\] Greatest side \[\propto \]\[\sin ({{126}^{o}})\] Smallest side \[\propto \] \[\sin ({{18}^{o}})\] and ratio\[=\FRAC{\sin {{126}^{o}}}{\sin ({{18}^{o}})}=\frac{\sqrt{5}+1}{\sqrt{5}-1}\].

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If the angles of a triangle be in the ratio 1 : 2 : 7, then the ratio of its greatest side to the least side is

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) 10 months ago

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\[x+2x+7x={{180}^{o}}\Rightarrow x={{18}^{o}}\] Hence the angles are \[{{18}^{o}},\text{ }{{36}^{o}},\text{ }{{126}^{o}}\] Greatest side \[\propto \]\[\sin ({{126}^{o}})\] Smallest side \[\propto \] \[\sin ({{18}^{o}})\] and ratio\[=\FRAC{\sin {{126}^{o}}}{\sin ({{18}^{o}})}=\frac{\sqrt{5}+1}{\sqrt{5}-1}\].

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Posted on 13 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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