COS \theta =\frac{49+16.3-13}{2.7.4\sqrt{3}}\RIGHTARROW \theta ={{30}^{o}}\].

"> COS \theta =\frac{49+16.3-13}{2.7.4\sqrt{3}}\RIGHTARROW \theta ={{30}^{o}}\].

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If the lengths of the sides of a triangle be \[7,4\sqrt{3}\] and \[\sqrt{13}\]cm, then the smallest angle is [MNR 1985]

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) 10 months ago

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\[\COS \theta =\frac{49+16.3-13}{2.7.4\sqrt{3}}\RIGHTARROW \theta ={{30}^{o}}\].

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Posted on 25 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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