SIN \frac{A}{2}=\SQRT{\frac{(s-b)(s-c)}{BC}}\] \[\Rightarrow bc{{\sin }^{2}}\frac{A}{2}=(s-b)(s-c)\] Hence\[x=bc\].

"> SIN \frac{A}{2}=\SQRT{\frac{(s-b)(s-c)}{BC}}\] \[\Rightarrow bc{{\sin }^{2}}\frac{A}{2}=(s-b)(s-c)\] Hence\[x=bc\].

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In a \[\Delta ABC\], if \[2s=a+b+c\]and \[(s-b)(s-c)=\] \[x{{\sin }^{2}}\frac{A}{2},\] then x = [MP PET 1992]

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) 10 months ago

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\[\SIN \frac{A}{2}=\SQRT{\frac{(s-b)(s-c)}{BC}}\] \[\Rightarrow bc{{\sin }^{2}}\frac{A}{2}=(s-b)(s-c)\] Hence\[x=bc\].

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Posted on 13 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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