X,y)\] is the curve\[|x|+|y|=1\]. If the point lies in the first quadrant, then \[x>0,y>0\] and so \[|x|+|y|=1\Rightarrow x+y=1\], which is straight line AB. If the point \[(x,\,y)\]lies in second quadrant then \[x<0\], \[y>0\] and so \[|x|+|y|=1\] Þ \[-x+y=1\] Similarly for third and fourth quadrant, the EQUATIONS are \[-x-y=1\]and \[x-y=1\]. Hence the required locus is the curve consisting of the SIDES of the SQUARE ABCD.