X}_{1}},{{y}_{1}})\] be the REQUIRED point.                    From \[P\,({{x}_{1}},{{y}_{1}})\], we draw PM and PN perpendicular to OX and OY respectively.            GIVEN, \[PM+PN=2\]                ......(i)                    But,     \[PM={{y}_{1}},PN={{x}_{1}}\]                    Hence from (i), \[{{y}_{1}}+{{x}_{1}}=2\]                    Thus locus of \[({{x}_{1}},{{y}_{1}})\]is \[x+y=2\]                    which is a straight line.

"> X}_{1}},{{y}_{1}})\] be the REQUIRED point.                    From \[P\,({{x}_{1}},{{y}_{1}})\], we draw PM and PN perpendicular to OX and OY respectively.            GIVEN, \[PM+PN=2\]                ......(i)                    But,     \[PM={{y}_{1}},PN={{x}_{1}}\]                    Hence from (i), \[{{y}_{1}}+{{x}_{1}}=2\]                    Thus locus of \[({{x}_{1}},{{y}_{1}})\]is \[x+y=2\]                    which is a straight line.

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The locus of a point so that sum of its distance from two given perpendicular lines is equal to 2 unit in first quadrant, is  [Bihar CEE 1994]

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) . 8 months ago

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We take the coordinate axes as two perpendicular lines. Let \[P\,({{X}_{1}},{{y}_{1}})\] be the REQUIRED point.                    From \[P\,({{x}_{1}},{{y}_{1}})\], we draw PM and PN perpendicular to OX and OY respectively.            GIVEN, \[PM+PN=2\]                ......(i)                    But,     \[PM={{y}_{1}},PN={{x}_{1}}\]                    Hence from (i), \[{{y}_{1}}+{{x}_{1}}=2\]                    Thus locus of \[({{x}_{1}},{{y}_{1}})\]is \[x+y=2\]                    which is a straight line.

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Posted on 10 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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