P(x)={{a}_{0}}+{{a}_{1}}{{x}^{2}}+{{a}_{2}}{{x}^{4}}+....+{{a}_{n}}{{x}^{2n}},x\in R\] and \[0<{{a}_{0}}<{{a}_{1}}<{{a}_{2}}<..... all="" also="" are="" coefficients="" different="" here="" i.e.="" observe="" of="" only="" positive.="" powers="" that="" we="" x="">EVEN powers of x are involved. THEREFORE, P(x) cannot have any maximum value. Moreover, P(x) is minimum, when x = 0, i.e., \[{{a}_{0}}.\] Therefore, P(x) has only one minimum.