COS }^{-1}}X=2{{\sin }^{-1}}x\] \[\Rightarrow \FRAC{\pi }{2}-{{\sin }^{-1}}x=2{{\sin }^{-1}}x\] \[\Rightarrow \frac{\pi }{2}=3{{\sin }^{-1}}x\Rightarrow {{\sin }^{-1}}x=\frac{\pi }{6}\] So, \[x=\sin \frac{\pi }{6}=\frac{1}{2}\]