1}}{{\left[ \frac{{{L}_{1}}}{{{L}_{2}}} \right]}^{1}}{{\left[ \frac{{{T}_{1}}}{{{T}_{2}}} \right]}^{-2}}=10{{\left[ \frac{meter}{km} \right]}^{1}}{{\left[ \frac{\SEC }{HR} \right]}^{-2}}\] \[{{n}_{2}}=10{{\left[ \frac{m}{{{10}^{3}}m} \right]}^{1}}{{\left[ \frac{\sec }{3600\sec } \right]}^{-2}}=129600\]

"> 1}}{{\left[ \frac{{{L}_{1}}}{{{L}_{2}}} \right]}^{1}}{{\left[ \frac{{{T}_{1}}}{{{T}_{2}}} \right]}^{-2}}=10{{\left[ \frac{meter}{km} \right]}^{1}}{{\left[ \frac{\SEC }{HR} \right]}^{-2}}\] \[{{n}_{2}}=10{{\left[ \frac{m}{{{10}^{3}}m} \right]}^{1}}{{\left[ \frac{\sec }{3600\sec } \right]}^{-2}}=129600\]

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If the acceleration due to gravity is \[10m{{s}^{-2}}\] and the units of length and time are changed in kilometer and hour respectively, what is the numerical value of the acceleration?

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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(129600) \[{{n}_{2}}={{n}_{1}}{{\left[ \frac{{{L}_{1}}}{{{L}_{2}}} \right]}^{1}}{{\left[ \frac{{{T}_{1}}}{{{T}_{2}}} \right]}^{-2}}=10{{\left[ \frac{meter}{km} \right]}^{1}}{{\left[ \frac{\SEC }{HR} \right]}^{-2}}\] \[{{n}_{2}}=10{{\left[ \frac{m}{{{10}^{3}}m} \right]}^{1}}{{\left[ \frac{\sec }{3600\sec } \right]}^{-2}}=129600\]

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Posted on 18 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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