CHANGE in MOMENTUM of ball             = \[\frac{MV-(-mv)}{t}=\frac{2mv}{t}\]

"> CHANGE in MOMENTUM of ball             = \[\frac{MV-(-mv)}{t}=\frac{2mv}{t}\]

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A ball of mass m moves with speed v and it strikes normally with a wall and reflected back normally, if its time of contact with wall is t then find force exerted by ball on wall                                       [BCECE 2005]                     

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 10 months ago

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For exerted by ball on wall = rate of CHANGE in MOMENTUM of ball             = \[\frac{MV-(-mv)}{t}=\frac{2mv}{t}\]

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Posted on 23 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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