CRITICAL CONDITION rope can bear only 2/3 of his weight. If a is the minimum acceleration then, Tension in the rope \[=m(G-a)\]= BREAKING strength             Þ \[m(g-a)=\frac{2}{3}MG\] Þ\[a=g-\frac{2g}{3}=\frac{g}{3}\]

"> CRITICAL CONDITION rope can bear only 2/3 of his weight. If a is the minimum acceleration then, Tension in the rope \[=m(G-a)\]= BREAKING strength             Þ \[m(g-a)=\frac{2}{3}MG\] Þ\[a=g-\frac{2g}{3}=\frac{g}{3}\]

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With what minimum acceleration can a fireman slides down a rope while breaking strength of the rope is \[\frac{2}{3}\] of his weight                            [CPMT 1979]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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If man slides down with some acceleration then its apparent weight decreases. For CRITICAL CONDITION rope can bear only 2/3 of his weight. If a is the minimum acceleration then, Tension in the rope \[=m(G-a)\]= BREAKING strength             Þ \[m(g-a)=\frac{2}{3}MG\] Þ\[a=g-\frac{2g}{3}=\frac{g}{3}\]

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