FRAC{F}{m} \right)\ t=\left( \frac{100}{5} \right)\TIMES 10=200\ cm/\sec \]

"> FRAC{F}{m} \right)\ t=\left( \frac{100}{5} \right)\TIMES 10=200\ cm/\sec \]

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A force of 100 dynes acts on a mass of 5 gram for 10 sec. The velocity produced is                           [Pb. PET 2004]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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\[v=u+at=0+\left( \FRAC{F}{m} \right)\ t=\left( \frac{100}{5} \right)\TIMES 10=200\ cm/\sec \]

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Posted on 28 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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