MAN,             \[R=m(g+a)=80(10+6)=1280\,N\]

"> MAN,             \[R=m(g+a)=80(10+6)=1280\,N\]

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A man of weight 80 kg is standing in an elevator which is moving with an acceleration of \[6\,\,m/{{s}^{2}}\] in upward direction. The apparent weight of the man will be \[(g=10\,m/{{s}^{2}})\]                        [DPMT 2003]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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The apparent weight of MAN,             \[R=m(g+a)=80(10+6)=1280\,N\]

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Posted on 29 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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