2A=(A+B)+(A-B)\] \[\RIGHTARROW \]\[\TAN 2A=\FRAC{\tan (A+B)+\tan (A-B)}{1-\tan (A+B)\tan (A-B)}=\frac{p+q}{1-pq}\].

"> 2A=(A+B)+(A-B)\] \[\RIGHTARROW \]\[\TAN 2A=\FRAC{\tan (A+B)+\tan (A-B)}{1-\tan (A+B)\tan (A-B)}=\frac{p+q}{1-pq}\].

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If \[\tan \,(A+B)=p,\,\,\tan \,(A-B)=q,\] then the value of \[\tan \,2A\] in terms of p and q is [MP PET 1995, 2002]

Mathematics Trigonometric Identities in Mathematics 1 year ago

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\[2A=(A+B)+(A-B)\] \[\RIGHTARROW \]\[\TAN 2A=\FRAC{\tan (A+B)+\tan (A-B)}{1-\tan (A+B)\tan (A-B)}=\frac{p+q}{1-pq}\].

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