WKWebView open links from certain domain in safari

Mobile Technologies Mobile Computing 2 years ago

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Posted on 16 Aug 2022, this text provides information on Mobile Computing related to Mobile Technologies. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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manpreet Tuteehub forum best answer Best Answer 2 years ago
_x000D_ You can implement WKNavigationDelegate, add the decidePolicyForNavigationAction method and check there the navigationType and requested url. I have used google.com below but you can just change it to your domain: Xcode 8.3 • Swift 3.1 or later import UIKit import WebKit class ViewController: UIViewController, WKNavigationDelegate { let webView = WKWebView() override func viewDidLoad() { super.viewDidLoad() webView.frame = view.bounds webView.navigationDelegate = self let url = URL(string: "https://www.google.com")! let urlRequest = URLRequest(url: url) webView.load(urlRequest) webView.autoresizingMask = [.flexibleWidth,.flexibleHeight] view.addSubview(webView) } func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) { if navigationAction.navigationType == .linkActivated { if let url = navigationAction.request.url, let host = url.host, !host.hasPrefix("www.google.com"), UIApplication.shared.canOpenURL(url) { UIApplication.shared.open(url) print(url) print("Redirected to browser. No need to open it locally") decisionHandler(.cancel) } else { print("Open it locally") decisionHandler(.allow) } } else { print("not a user click") decisionHandler(.allow) } } }

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