KX]\]= Dimension of \[\omega t=\](DIMENSIONLESS) HENCE \[K=\frac{1}{X}=\frac{1}{L}=\left[ {{L}^{-1}} \RIGHT]\]  \ \[[K]=[{{L}^{-1}}]\]

"> KX]\]= Dimension of \[\omega t=\](DIMENSIONLESS) HENCE \[K=\frac{1}{X}=\frac{1}{L}=\left[ {{L}^{-1}} \RIGHT]\]  \ \[[K]=[{{L}^{-1}}]\]

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In the relation \[y=a\cos (\omega t-kx)\], the dimensional formula for k is?                             [BHU 2004]

NEET Physics in NEET 1 year ago

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\[[KX]\]= Dimension of \[\omega t=\](DIMENSIONLESS) HENCE \[K=\frac{1}{X}=\frac{1}{L}=\left[ {{L}^{-1}} \RIGHT]\]  \ \[[K]=[{{L}^{-1}}]\]

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