N}}\]             \[\LEFT[ {{M}^{0}}L{{T}^{0}} \RIGHT]={{\left[ L{{T}^{-2}} \right]}^{m}}{{\left[ T \right]}^{n}}=\left[ {{L}^{m}}{{T}^{-2m+n}} \right]\]             \[\therefore \] \[m=1\] and \[-2m+n=0\]Þ \[n=2\].

"> N}}\]             \[\LEFT[ {{M}^{0}}L{{T}^{0}} \RIGHT]={{\left[ L{{T}^{-2}} \right]}^{m}}{{\left[ T \right]}^{n}}=\left[ {{L}^{m}}{{T}^{-2m+n}} \right]\]             \[\therefore \] \[m=1\] and \[-2m+n=0\]Þ \[n=2\].

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 Position of a body with acceleration 'a' is given by \[x=K{{a}^{m}}{{t}^{n}},\]here t is time. Find dimension of m and n?                                                                                         [Orissa JEE 2005]

NEET Physics in NEET 1 year ago

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As \[x=K{{a}^{m}}\times {{t}^{N}}\]             \[\LEFT[ {{M}^{0}}L{{T}^{0}} \RIGHT]={{\left[ L{{T}^{-2}} \right]}^{m}}{{\left[ T \right]}^{n}}=\left[ {{L}^{m}}{{T}^{-2m+n}} \right]\]             \[\therefore \] \[m=1\] and \[-2m+n=0\]Þ \[n=2\].

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Posted on 27 Aug 2024, this text provides information on NEET related to Physics in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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