FORMULA for horizontal range is R = v2 (SIN 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on SOLVING we will GET range as 54.13 m.

"> FORMULA for horizontal range is R = v2 (SIN 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on SOLVING we will GET range as 54.13 m.

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A body of mass 5 kg, projected at an angle of 60° from the ground with an initial velocity of 25 m/s, acceleration due to gravity is g = 10 m/s2, what is the maximum horizontal range covered?

Physics Simple Projectile Motion in Physics . 6 months ago

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The FORMULA for horizontal range is R = v2 (SIN 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on SOLVING we will GET range as 54.13 m.

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Posted on 26 Nov 2024, this text provides information on Physics related to Simple Projectile Motion in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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