The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance \[5\times {{10}^{-11}}m,\] will be (Charge on electron \[=\text{ 1}.\text{6}\times \text{1}{{0}^{\text{19}}}C\], mass of electron \[=\text{ 9}.\text{1}\times \text{1}{{0}^{\text{31}}}kg\], mass of proton = \[1.6\times {{10}^{-27}}kg,\] \[\,G=6.7\times {{10}^{-11}}\,N{{m}^{2}}/k{{g}^{2}})\]                  [RPET 1997; Pb PMT 2003]

QuestionBank Joint Entrance Exam - Main (JEE Main) 1 year ago

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Option 1 : \[\text{2}.\text{36}\times \text{1}{{0}^{\text{39}}}\]

Option 2 : \[\text{2}.\text{36}\times \text{1}{{0}^{40}}\]

Option 3 : \[\text{2}.\text{34}\times \text{1}{{0}^{41}}\]

Option 4 : \[\text{2}.\text{34}\times \text{1}{{0}^{42}}\]


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SalTupTC SalTupTC Tuteehub forum best answer Best Answer 1 year ago
\[\text{2}.\text{36}\times \text{1}{{0}^{40}}\]


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