ADC;∠ADC = ∠BAC (Given), ∠C is COMMON and AC is common;∴ Triangle BAC and triangle ADC are SIMILAR triangles;∴ BC/AC = AC/DC⇒ 12/AC = AC/3⇒ AC = 6 cm

"> ADC;∠ADC = ∠BAC (Given), ∠C is COMMON and AC is common;∴ Triangle BAC and triangle ADC are SIMILAR triangles;∴ BC/AC = AC/DC⇒ 12/AC = AC/3⇒ AC = 6 cm

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ABC is a triangle and D is a point on the side BC. If BC = 12 cm, BD = 9 cm and ∠ADC = ∠BAC, then the length of AC is equal to

SRMJEEE Analytical Geometry in SRMJEEE 1 year ago

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In the figure;Observing triangle BAC and triangle ADC;∠ADC = ∠BAC (Given), ∠C is COMMON and AC is common;∴ Triangle BAC and triangle ADC are SIMILAR triangles;∴ BC/AC = AC/DC⇒ 12/AC = AC/3⇒ AC = 6 cm

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Posted on 29 Oct 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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