4 CMCD = 5 cmConcept used:In ΔABC, RIGHT angle at BAD is PERPENDICULAR to BC, thenAD2 = BD × DCCalculation:According to propertyAD2 = BD × DC⇒ AD2 = 4 × 5⇒ AD = √20⇒ AD = 2√5 cm∴ The AD is 2√5 cm.

"> 4 CMCD = 5 cmConcept used:In ΔABC, RIGHT angle at BAD is PERPENDICULAR to BC, thenAD2 = BD × DCCalculation:According to propertyAD2 = BD × DC⇒ AD2 = 4 × 5⇒ AD = √20⇒ AD = 2√5 cm∴ The AD is 2√5 cm.

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In a ΔABC, ∠BAC = 90° and AD is perpendicular to BC where D is a point on BC. If BD = 4 cm and CD = 5 cm, then the length of AD is equal to:

SRMJEEE Analytical Geometry in SRMJEEE 9 months ago

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Given:∠BAC = 90°BD = 4 CMCD = 5 cmConcept used:In ΔABC, RIGHT angle at BAD is PERPENDICULAR to BC, thenAD2 = BD × DCCalculation:According to propertyAD2 = BD × DC⇒ AD2 = 4 × 5⇒ AD = √20⇒ AD = 2√5 cm∴ The AD is 2√5 cm.

Posted on 01 Nov 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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