LET one side of quadrilateral be x and another side be y so, \[2(x+y)=34\] or, \[(x+y)=17....(i)\] We know from the basic PRINCIPLE that for a given perimeter square has the MAXIMUM area, so, x = y and putting this value in equation (i) \[x=y=\frac{17}{2}\] Area \[=x.y=\frac{17}{2}\times \frac{17}{2}=\frac{289}{4}=72.25\]