LINE = 5x + 3y = 15Concept Used:In this TYPE of question, since the given line cuts y-axis, so co-ordinate of y - axis can be CALCULATED by putting X = 0Formula Used:Putting the value of x = 0, in the given equation of line, co-ordinate of y - axis can be DETERMINED and so the required pointCalculation:Using the above formulae, we get⇒ Co-ordinate of y - axis = 5 × 0 + 3y = 15⇒ y = 5∴ Required point = (0, 5)

"> LINE = 5x + 3y = 15Concept Used:In this TYPE of question, since the given line cuts y-axis, so co-ordinate of y - axis can be CALCULATED by putting X = 0Formula Used:Putting the value of x = 0, in the given equation of line, co-ordinate of y - axis can be DETERMINED and so the required pointCalculation:Using the above formulae, we get⇒ Co-ordinate of y - axis = 5 × 0 + 3y = 15⇒ y = 5∴ Required point = (0, 5)

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At what point does the line 5x + 3y = 15 cuts the y-axis?

SRMJEEE Analytical Geometry in SRMJEEE 1 year ago

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Given:Equation of LINE = 5x + 3y = 15Concept Used:In this TYPE of question, since the given line cuts y-axis, so co-ordinate of y - axis can be CALCULATED by putting X = 0Formula Used:Putting the value of x = 0, in the given equation of line, co-ordinate of y - axis can be DETERMINED and so the required pointCalculation:Using the above formulae, we get⇒ Co-ordinate of y - axis = 5 × 0 + 3y = 15⇒ y = 5∴ Required point = (0, 5)

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Posted on 20 Oct 2024, this text provides information on SRMJEEE related to Analytical Geometry in SRMJEEE. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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